Найдите значение дроби: (10xy-5x^2)/(8y^2-4xy) при x=1/5; y=1/6.

\[\frac{10xy - 5x^{2}}{8y^{2} - 4xy} = \frac{5x(2y - x)}{4y(2y - x)} =\]

\[= \frac{5x}{4y}\]

\[x = \frac{1}{5};\ \ y = \frac{1}{6}:\]

\[\frac{5x}{4y} = \frac{5 \cdot \frac{1}{5}}{4 \cdot \frac{1}{6}} = \frac{1}{\frac{2}{3}} = \frac{3}{2} = 1,5.\]