\[\ \frac{1^{\backslash 4p - q}}{4p + q} - \frac{1^{\backslash 4p + q}}{4p - q} = \frac{4p - q - 4p - q}{16p^{2} - q^{2}} =\]
\[= \frac{- 2q}{16p^{2} - q^{2}} = \frac{2q}{q^{2} - 16p^{2}}\]