\[\frac{8}{\sqrt{7} - 1} = \frac{8\left( \sqrt{7} + 1 \right)}{\left( \sqrt{7} - 1 \right)\left( \sqrt{7} + 1 \right)} =\]
\[= \frac{8\left( \sqrt{7} + 1 \right)}{7 - 1} = \frac{8\left( \sqrt{7} + 1 \right)}{6} =\]
\[= \frac{4}{3}\left( \sqrt{7} + 1 \right) = 1\frac{1}{3}\left( \sqrt{7} + 1 \right)\]