\[y = x^{2} + 2x - 9;\ \ \ y = \frac{18}{x}\]
\[x^{2} + 2x - 9 = \frac{18}{x}\ \ \ \ \ \ | \cdot x\]
\[x^{3} + 2x^{2} - 9x - 18 = 0\]
\[x^{2}(x + 2) - 9(x + 2) = 0\]
\[(x + 2)\left( x^{2} - 9 \right) = 0\]
\[(x + 2)(x - 3)(x + 3) = 0\]
\[x = - 2;\ \ \ x = 3;\ \ \ x = - 3\]
\[y = - 9;\ \ y = 6;\ \ \ y = - 6\]
\[Ответ:графики\ пересекаются\ \]
\[в\ точках\ ( - 2;\ - 9);(3;6);\]
\[( - 3;\ - 6).\]