\[\left( \frac{2}{3} \right)^{- 3} \cdot 9^{- 2} = \left( \frac{3}{2} \right)^{3} \cdot \frac{1}{81} =\]
\[= \frac{27 \cdot 1}{8 \cdot 81} = \frac{1}{24}\]