\[\left( \frac{3}{8} \right)^{- 1} + 3^{- 2} - ( - 2,6)^{0} =\]
\[= \frac{8^{\backslash 3}}{3} + \frac{1}{9} - 1^{\backslash 9} = \frac{24 + 1 - 9}{9} =\]
\[= \frac{16}{9} = 1\frac{7}{9}\]