Найдите область определения функции y=корень из (7x-2x^2)+(2x+3)/(9-x^2).

\[y = \sqrt{7x - 2x^{2}} + \frac{2x + 3}{9 - x^{2}}\]

\[\left\{ \begin{matrix} 7x - 2x^{2} \geq 0 \\ 9 - x^{2}
eq 0\ \ \ \ \ \\ \end{matrix} \right.\ \]

\[7x - 2x^{2} \geq 0\]

\[2x^{2} - 7x \leq 0\]

\[2x(x - 3,5) \leq 0\]

\[0 \leq x \leq 3,5.\]

\[\left\{ \begin{matrix} x \geq 0\ \ \ \\ x \leq 3,5 \\ x
eq - 3 \\ x
eq 3\ \ \ \\ \end{matrix} \right.\ \]

\[D(y) = \lbrack 0;3) \cup (3;3,5\rbrack.\]