Найдите корни уравнения: 5/(y+3)-3/y=(2-y)/(y^2+3y).

\[\frac{5}{y + 3} - \frac{3}{y} = \frac{2 - y}{y^{2} + 3y}\]

\[ОДЗ:\ \ y \neq 0;\]

\[\ \ \ \ \ \ \ \ \ \ \ y \neq - 3\]

\[\frac{5y - 3 \cdot (y + 3)}{y² + 3y} = \frac{2 - y}{y² + 3y}\]

\[5y - 3y - 9 = 2 - y\]

\[2y - 9 = 2 - y\]

\[3y = 11\]

\[y = \frac{11}{3}\]

\[y = 3\frac{2}{3}\]

\[Ответ:\ \ y = 3\frac{2}{3}.\]