Найдите корни уравнения: (4y+7)/(2y-3)-(y-3)/(2y+3)=1.

\[\frac{4y + 7}{2y - 3} - \frac{y - 3}{2y + 3} = 1\]

\[ОДЗ:\ \ x \neq - 1,5\]

\[\ \ \ \ \ \ \ \ \ \ \ x \neq 1,5\]

\[2y^{2} + 35y + 21 = 0\]

\[D = b^{2} - 4ac =\]

\[= 1225 - 4 \cdot 2 \cdot 21 =\]

\[= 1225 - 168 = 1057\]

\[y_{1} = \frac{- 35 + \sqrt{1057}}{4}\]

\[y_{2} = \frac{- 35 - \sqrt{1057}}{4}\ \]

\[Ответ:y = \frac{- 35 + \sqrt{1057}}{4};\ \ \ \]

\[y = \frac{- 35 - \sqrt{1057}}{4}.\]