Решение:
1) $3(x - 2) = x + 2$
$3x - 6 = x + 2$
$3x - x = 2 + 6$
$2x = 8$
$x = \frac{8}{2}$
$x = 4$
2) $5 - 2(x - 1) = 4 - x$
$5 - 2x + 2 = 4 - x$
$7 - 2x = 4 - x$
$-2x + x = 4 - 7$
$-x = -3$
$x = 3$
3) $(7x + 1) - (9x + 3) = 5$
$7x + 1 - 9x - 3 = 5$
$-2x - 2 = 5$
$-2x = 5 + 2$
$-2x = 7$
$x = -\frac{7}{2}$
$x = -3,5$
4) $3,4 + 2y = 7(y - 2,3)$
$3,4 + 2y = 7y - 16,1$
$2y - 7y = -16,1 - 3,4$
$-5y = -19,5$
$y = \frac{-19,5}{-5}$
$y = 3,9$
5) $0,2(7 - 2y) = 2,3 - 0,3(y - 6)$
$1,4 - 0,4y = 2,3 - 0,3y + 1,8$
$1,4 - 0,4y = 4,1 - 0,3y$
$-0,4y + 0,3y = 4,1 - 1,4$
$-0,1y = 2,7$
$y = \frac{2,7}{-0,1}$
$y = -27$
6) $\frac{2}{3}(\frac{1}{3}x - \frac{1}{2}) = 4x + 2\frac{1}{2}$
$\frac{2}{9}x - \frac{2}{6} = 4x + \frac{5}{2}$
$\frac{2}{9}x - \frac{1}{3} = 4x + \frac{5}{2}$
$\frac{2}{9}x - 4x = \frac{5}{2} + \frac{1}{3}$
$\frac{2}{9}x - \frac{36}{9}x = \frac{15}{6} + \frac{2}{6}$
$-\frac{34}{9}x = \frac{17}{6}$
$x = \frac{17}{6} \cdot (-\frac{9}{34})$
$x = -\frac{1}{2} \cdot \frac{3}{2}$
$x = -\frac{3}{4}$
$x = -0,75$
**Ответы:**
1) $x = 4$
2) $x = 3$
3) $x = -3,5$
4) $y = 3,9$
5) $y = -27$
6) $x = -0,75$
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