\[y = 8x^{2};\ \ y = 16x;\]
\[8x^{2} = 16x\]
\[8x^{2} - 16x = 0\]
\[8x(x - 2) = 0\]
\[x_{1} = 0;\ \ x_{2} = 2;\]
\[y_{1} = 16 \cdot 0 = 0;\]
\[y_{2} = 16 \cdot 2 = 32.\]
\[Ответ:(0;0);(2;32).\]