\[y = 0\ \ \ \ \ \ \ и\ \ \ \ y = \frac{x² - 2x - 15}{x + 3}\]
\[\frac{x^{2} - 2x - 15}{x + 3} = 0\]
\[ОДЗ:\ \ x \neq - 3\]
\[x^{2} - 2x - 15 = 0\]
\[x_{1} + x_{2} = 2\]
\[x_{1} \cdot x_{2} = - 15 \Longrightarrow x_{1} = 5;\ \ \]
\[x_{2} = - 3\ (не\ подходит\ по\ ОДЗ)\]
\[Ответ:(5;0).\]