1) 18ab^5;
2) 6a^2b^10.
\[6ab^{5} = - 7\]
\[ab^{5} = - \frac{7}{6}\]
\[1)\ 18ab^{5} = 3 \cdot 6ab^{5} = 3 \cdot ( - 7) = - 21.\]
\[2)\ 6a^{2}b^{10} = 6 \cdot \left( ab^{5} \right)^{2} = 6 \cdot \left( - \frac{7}{6} \right)^{2} =\]
\[= 6 \cdot \frac{49}{36} = \frac{49}{6} = 8\frac{1}{6}.\]