Решебник по математике 6 класс Виленкин ФГОС Часть 1, 2 Часть 2. П. 6. Координаты на плоскости Задание 7

\[\boxed{\mathbf{6.7}}\]

\[\textbf{а)}\ 3a - 4 = 2a + 6\]

\[3a - 2a = 6 + 4\]

\[a = 10.\]

\[\textbf{б)}\ \frac{4}{7}x + \frac{3}{7} = \frac{1}{7}x\]

\[\frac{4}{7}x - \frac{1}{7}x = - \frac{3}{7}\]

\[\frac{3}{7}x = - \frac{3}{7}\]

\[x = - 1.\]

\[\textbf{в)}\ 1,7y - 1 = 1,3y + 1,4\]

\[1,7y - 1,3y = 1,4 + 1\]

\[0,4y = 2,4\]

\[y = 2,4\ :0,4 = 24\ :4\]

\[y = 6.\]

\[\textbf{г)}\ \frac{4^{\backslash 3}}{7}x = \frac{4}{21}x - \frac{8}{21}\ \]

\[\frac{12}{21}x - \frac{4}{21}x = - \frac{8}{21}\]

\[\frac{8}{21}x = - \frac{8}{21}\]

\[x = - 1.\]