Решебник по математике 6 класс Ткачева ФГОС рабочая тетрадь | Страница 84

Авторы:
Год:2023

Страница 84

\[Страница\ 84.\]

\[\boxed{\mathbf{8.}}\]

\[\textbf{а)}\ 2\frac{1}{3} = \frac{7}{3}\]

\[7\frac{1}{4} = \frac{29}{4}\]

\[5\frac{2}{7} = \frac{37}{7}\]

\[\textbf{б)}\ 8\frac{1}{6} = \frac{49}{6}\]

\[40\frac{2}{3} = \frac{122}{3}\]

\[2\frac{2}{35} = \frac{72}{35}\]

\[\textbf{в)}\ 3,6 = \frac{36}{10} = \frac{18}{5}\]

\[2,8 = \frac{28}{10} = \frac{14}{5}\]

\[10,5 = \frac{105}{10} = \frac{21}{2}\]

\[\boxed{\mathbf{9.}}\]

\[\textbf{а)}\ 18\ :10\frac{7}{20} = 18\ :\frac{207}{20} =\]

\[= 18 \cdot \frac{20}{207} = \frac{40}{23} = 1\frac{17}{23}\]

\[4\frac{1}{2}\ :\frac{2}{3} = \frac{9}{2} \cdot \frac{3}{2} = \frac{27}{4} = 6\frac{3}{4}\]

\[5\frac{17}{24}\ :\frac{2}{3} = \frac{137}{24} \cdot \frac{3}{2} = \frac{137}{16} = 8\frac{9}{16}\]

\[\textbf{б)}\ 17\frac{5}{14} \cdot 2\frac{2}{27} = \frac{243}{14} \cdot \frac{56}{27} =\]

\[= 9 \cdot 4 = 36\]

\[39\ :9\frac{3}{5} = 39\ :\frac{48}{5} = 39 \cdot \frac{5}{48} =\]

\[= \frac{65}{16} = 4\frac{1}{16}\]

\[\frac{7}{12}\ :3\frac{1}{16} = \frac{7}{12}\ :\frac{49}{16} = \frac{7}{12} \cdot \frac{16}{49} =\]

\[= \frac{4}{21}\]

\[\textbf{в)}\ 63\frac{1}{3}\ :5\frac{2}{11} = \frac{190}{3}\ :\frac{57}{11} =\]

\[= \frac{190}{3} \cdot \frac{11}{57} = 12\frac{38}{171}\]

\[6\frac{1}{8}\ :3\frac{1}{2} = \frac{49}{8}\ :\frac{7}{2} = \frac{49}{8} \cdot \frac{2}{7} = \frac{7}{4} =\]

\[= 1\frac{3}{4}\]

\[5\frac{9}{11}\ :13\frac{5}{7} = \frac{64}{11}\ :\frac{96}{7} = \frac{64}{11} \cdot \frac{7}{96} =\]

\[= \frac{14}{33}\]

\[\textbf{г)}\ 32\ :9\frac{3}{5} = 32\ :\frac{48}{5} = 32 \cdot \frac{5}{48} =\]

\[= \frac{10}{3} = 3\frac{1}{3}\]

\[25\frac{5}{7}\ :1\frac{1}{35} = \frac{180}{7}\ :\frac{36}{35} =\]

\[= \frac{180}{7} \cdot \frac{35}{36} = 25\]

\[21\frac{7}{9}\ :4\frac{2}{3} = \frac{196}{9}\ :\frac{14}{3} =\]

\[= \frac{196}{9} \cdot \frac{3}{14} = \frac{14}{3} = 4\frac{2}{3}\]

Скачать ответ
Есть ошибка? Сообщи нам!

Решебники по другим предметам