Решебник по математике 6 класс Ткачева ФГОС рабочая тетрадь | Страница 73

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\[\boxed{\mathbf{11.}}\]

\[5\frac{1}{3} \cdot \frac{5}{6} = \frac{16}{3} \cdot \frac{5}{6} = \frac{40}{9} = 4\frac{4}{9}\]

\[5\frac{1}{3} - \frac{5}{6} = \frac{16}{3} - \frac{5}{6} = \frac{32}{6} - \frac{5}{6} =\]

\[= \frac{27}{6} = 4\frac{1}{2}\]

\[\frac{1}{2} = \frac{9}{18};\ \ \ \ \frac{4}{9} = \frac{8}{18};\ \ \ \ \frac{9}{18} > \frac{8}{18}.\]

\[\boxed{\mathbf{12.}}\]

\[\textbf{а)}\ 1 \cdot 3 + 1 \cdot 4 = 1 + 4 = 7\ см^{2}.\]

\[\textbf{б)}\ 1 \cdot 2 + 1 \cdot 5 + 1 \cdot 1 + 1 \cdot 1 =\]

\[= 9\ см^{2}.\]

\[\textbf{в)}\ 1 \cdot 4 + 1 \cdot 2 + 1 \cdot 1 = 7\ см^{2}.\]

\[Ответ:а)\ 7\ см^{2};\ \ б)\ 9\ см^{2};\ \ \ \]

\[\textbf{в)}\ 7\ см^{2}\text{.\ }\]