Решебник по математике 6 класс Ткачева ФГОС рабочая тетрадь | Страница 67

\[Страница\ 67.\]

\[\boxed{\mathbf{8.}}\]

\[7 - 1 = 6\ мин =\]

\[= 360\ сек. - пчела\ была\ \]

\[в\ полете.\]

\[\left( (4 + 2)\ :2 \cdot 360 \right)\ :2 =\]

\[= 1080\ :2 = 540\ (м) -\]

\[расстояние\ от\ улья\ до\ липы.\]

\[Ответ:540\ м.\]

\[\boxed{\mathbf{9.}}\]

\[15\frac{5^{\backslash 9}}{6} - 9\frac{25^{\backslash 2}}{27} = 15\frac{45}{54} - 9\frac{50}{54} =\]

\[= 14\frac{99}{54} - 9\frac{50}{54} = 5\frac{49}{54}\]

\[\frac{2^{\backslash 6}}{3} - \frac{5}{18} = \frac{12}{18} - \frac{5}{18} = \frac{7}{18}\]

\[\frac{7^{\backslash 2}}{27} + \frac{13^{\backslash 3}}{18} = \frac{14}{54} + \frac{39}{54} = \frac{53}{54}\]

\[5\frac{49}{54} - \frac{7^{\backslash 3}}{18} + \frac{53}{54} = 5\frac{102}{54} - \frac{21}{54} =\]

\[= 5\frac{81}{54} = 6\frac{27}{54} = 6\frac{1}{2}.\]

\[Ответ:6\frac{1}{2}.\]

\[3\frac{1^{\backslash 3}}{3} + 5\frac{7}{9} = 3\frac{3}{9} + 5\frac{7}{9} = 8\frac{10}{9} =\]

\[= 9\frac{1}{9}\]

\[9\frac{1}{9} \cdot 2\frac{1}{4} = \frac{82}{9} \cdot \frac{9}{4} = \frac{41}{2} = 20\frac{1}{2}\]

\[3\frac{5^{\backslash 4}}{6} - \frac{7^{\backslash 2}}{12} + 9\frac{7^{\backslash 3}}{8} =\]

\[= 3\frac{20}{24} - \frac{14}{24} + 9\frac{21}{24} =\]

\[= 12\frac{41}{24} - \frac{14}{24} = 12\frac{27}{24} = 12\frac{9}{8} =\]

\[= 13\frac{1}{8}\]

\[1\frac{1}{15} \cdot 13\frac{1}{8} = \frac{16}{15} \cdot \frac{105}{8} = 2 \cdot 7 =\]

\[= 14\]

\[20\frac{1}{2} - 14 = 6\frac{1}{2}\]

\[6\frac{1}{2} \cdot \frac{16}{39} = \frac{13}{2} \cdot \frac{16}{39} = \frac{8}{3} = 2\frac{2}{3}\]

\[Ответ:2\frac{2}{3}.\]