Решебник по математике 6 класс Ткачева ФГОС рабочая тетрадь | Страница 56

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\[\boxed{\mathbf{2.}}\]

\[\textbf{а)}\ 2\frac{2}{5} + 7\frac{3}{10} = 9 + \frac{4}{10} + \frac{3}{10} =\]

\[= 9\frac{7}{10}\]

\[\textbf{б)}\ 6\frac{7}{8} + 3\frac{5}{12} = 9 + \frac{21}{24} + \frac{10}{24} =\]

\[= 9 + \frac{31}{24} = 9\frac{31}{24} = 10\frac{7}{24}\]

\[\textbf{в)}\ 8\frac{1}{9} + 2\frac{3}{5} = 10 + \frac{5}{45} + \frac{27}{45} =\]

\[= 10\frac{32}{45}\]

\[\textbf{г)}\ 9\frac{2}{7} + 5 = 14\frac{2}{7}\]

\[\textbf{д)}\ 5 + 2\frac{11}{19} = 7\frac{11}{19}\]

\[\textbf{е)}1 - \frac{3}{7} = \frac{7}{7} - \frac{3}{7} = \frac{4}{7}\]

\[\textbf{ж)}\ 8 - \frac{9}{11} = 7\frac{11}{11} - \frac{9}{11} = 7\frac{2}{11}\]

\[\textbf{з)}\ 5 - 2\frac{3}{5} = 4\frac{5}{5} - 2\frac{3}{5} = 2\frac{2}{5}\]

\[\textbf{и)}\ 3\frac{2}{9} + 6 = 9\frac{2}{9}\]

\[к)\ 5\frac{2}{13} + 7\frac{11}{13} = 12\frac{13}{13} = 13\]

\[л)\ 3 - \frac{5}{6} = 2\frac{6}{6} - \frac{5}{6} = 2\frac{1}{6}\]

\[м)\ 9 - 2\frac{8}{9} = 8\frac{9}{9} - 2\frac{8}{9} = 6\frac{1}{9}\]

\[н)\ 5 - 4\frac{3}{8} = 4\frac{8}{8} - 4\frac{3}{8} = \frac{5}{8}\]