Решебник по математике 6 класс Перова рабочая тетрадь | Страница 51

\[\boxed{\text{162.}}\]

\[\frac{8}{3} = 2\frac{2}{3}\]

\[\frac{23}{2} = 11\frac{1}{2}\]

\[\frac{46}{5} = 9\frac{1}{5}\]

\[\frac{11}{11} = 1\]

\[\frac{37}{6} = 6\frac{1}{6}\]

\[\frac{14}{2} = 2\]

\[\frac{52}{7} = 7\frac{3}{7}\]

\[\boxed{\text{163.}}\]

\[\frac{7}{3} = 2\frac{1}{3}\]

\[2\frac{1}{4} = \frac{9}{4}\]

\[2\frac{1}{2} = \frac{5}{2}\]

\[\boxed{\text{164.}}\]

\[\frac{4}{8} = \frac{2}{4} = \frac{1}{2}\]

\[\frac{9}{24} = \frac{3}{8}\]

\[\frac{16}{24} = \frac{8}{12} = \frac{4}{6}\]

\[\frac{18}{30} = \frac{9}{15} = \frac{3}{5}\]

\[\boxed{\text{165.}}\]

\[\frac{2}{3} = \frac{4}{6}\]

\[\frac{4}{5} = \frac{8}{10}\]

\[\frac{5}{7} = \frac{10}{14}\]

\[\frac{7}{9} = \frac{14}{18}\]

\[\frac{11}{6} = \frac{22}{12}\]

\[\frac{6}{7} = \frac{12}{14}\]

\[\frac{2}{7} = \frac{6}{21}\]