Решебник по математике 6 класс Перова рабочая тетрадь | Страница 49

\[\boxed{\text{153.}}\]

\[3\frac{1}{8} < 3\frac{5}{8}\]

\[6\frac{1}{9} > 3\frac{4}{9}\]

\[2\frac{1}{7} < 4\frac{4}{7}\]

\[8\frac{3}{11} < 8\frac{5}{11}\]

\[9\frac{6}{13} > 8\frac{9}{13}\]

\[1\frac{1}{2} < 2\]

\[\boxed{\text{154.}}\]

\[3\frac{1}{4} > 3\frac{3}{4}\]

\[2\frac{2}{5} < 2\frac{3}{5}\]

\[5\frac{1}{9} < 5\frac{7}{9}\]

\[4\frac{2}{7} = 4\frac{2}{7}\]

\[3\frac{1}{3} = 3\frac{1}{3}\]

\[1\frac{4}{5} > 1\frac{2}{5}\]

\[\boxed{\text{155.}}\]

\[От\ большего\ к\ меньшему:\]

\[11\frac{3}{5};\ \ \ 7\frac{3}{5};\ \ 7\frac{2}{5};\ \ 5\frac{3}{5};\ \ 5\frac{1}{5};\ \ 1\frac{4}{5}.\]

\[\boxed{\text{156.}}\]

\[\frac{1}{5} = \frac{2}{10}\]

\[\frac{2}{3} = \frac{6}{9}\]

\[\frac{3}{7} = \frac{9}{21}\]

\[\frac{1}{2} = \frac{9}{18}\]

\[\frac{3}{8} = \frac{15}{40}\]

\[\frac{4}{11} = \frac{16}{44}\]

\[\boxed{\text{157.}}\]

\[\frac{2}{4} = \frac{1}{2}\]

\[\frac{9}{12} = \frac{3}{4}\]

\[\frac{5}{10} = \frac{1}{2}\]

\[\frac{7}{21} = \frac{1}{3}\]

\[\frac{8}{48} = \frac{1}{6}\]

\[\frac{9}{81} = \frac{1}{9}\]

\[\frac{4}{24} = \frac{1}{6}\]

\[\frac{6}{42} = \frac{1}{7}\]