Решебник по математике 6 класс Ерина Виленкин рабочая тетрадь Часть 1, 2 Часть 1 | Страница 85

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\[\boxed{\mathbf{10.}}\]

\[10\frac{8}{9} = 10 + \frac{8}{9};а\ потом\ \]

\[воспользуемся\ \]

\[распределительным\ законом\]

\[деления\ относительно\ \]

\[сложения.\]

\[\boxed{\mathbf{11.}}\]

\[\textbf{а)}\ 16\frac{8}{9}\ :8 = 16\ :8 + \frac{8}{9}\ :8 =\]

\[= 2 + \frac{1}{9} = 2\frac{1}{9}\]

\[34\frac{4}{9}\ :2 = 34\ :2 + \frac{4}{9}\ :2 =\]

\[= 17 + \frac{2}{9} = 17\frac{2}{9}\]

\[35\frac{5}{8}\ :5 = 35\ :5 + \frac{5}{8}\ :5 =\]

\[= 7 + \frac{1}{8} = 7\frac{1}{8}\]

\[\textbf{б)}\ 120\frac{6}{7}\ :3 = 120\ :3 + \frac{6}{7}\ :3 =\]

\[= 40 + \frac{2}{7} = 40\frac{2}{7}\]

\[14\frac{7}{13}\ :7 = 14\ :7 + \frac{7}{13}\ :7 =\]

\[= 2 + \frac{1}{13} = 2\frac{1}{13}\]

\[26\frac{8}{11}\ :2 = 26\ :2 + \frac{8}{11}\ :2 =\]

\[= 13 + \frac{4}{11} = 13\frac{4}{11}\]

\[\textbf{в)}\ 64\frac{16}{21}\ :4 = 64\ :4 + \frac{16}{21}\ :4 =\]

\[= 16 + \frac{4}{21} = 16\frac{4}{21}\]

\[38\frac{6}{11}\ :2 = 38\ :2 + \frac{6}{11}\ :2 =\]

\[= 19 + \frac{3}{11} = 19\frac{3}{11}\]

\[100\frac{50}{109}\ :25 =\]

\[= 100\ :25 + \frac{50}{109}\ :25 = 4\frac{2}{109}\]

\[\boxed{\mathbf{12.}}\]

\[\textbf{а)}\frac{7}{8}\ :\frac{3}{4} > 1\]

\[\textbf{б)}\ 5\frac{9}{11}\ :13\frac{5}{7} < 1\]

\[\textbf{в)}\ 18\ :10\frac{7}{20} > 1\]

\[\textbf{г)}\frac{7}{12}\ :\frac{5}{6} < 1\ \]