Решебник по математике 6 класс Ерина Виленкин рабочая тетрадь Часть 1, 2 Часть 1 | Страница 58

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\[\boxed{\mathbf{5.}}\]

\[\textbf{а)}\ 5\frac{7}{8} + 6 = 11\frac{7}{8}\]

\[7 + 1\frac{1}{8} = 8\frac{1}{8}\]

\[1 + \frac{3}{5} = 1\frac{3}{5}\]

\[\textbf{б)}\ 4\frac{7}{9} - 3 = 1\frac{7}{9}\]

\[5\frac{1}{3} - 5 = \frac{1}{3}\]

\[9\frac{3}{7} - \frac{3}{7} = 9\]

\[\textbf{в)}\frac{7}{9} + 3 = 3\frac{7}{9}\]

\[1 - \frac{3}{5} = \frac{5}{5} - \frac{3}{5} = \frac{2}{5}\]

\[1 - \frac{7}{8} = \frac{8}{8} - \frac{7}{8} = \frac{1}{8}\]

\[\textbf{г)}\ 6\frac{4}{5} + \frac{1}{5} = 7\]

\[1 - \frac{1}{2} = \frac{1}{2}\]

\[1 - \frac{3}{4} = \frac{1}{4}\]

\[\boxed{\mathbf{6.}}\]

\[\textbf{а)}\ 7\frac{5}{5} = 8\]

\[10\frac{8}{8} = 11\]

\[16\frac{2}{2} = 17\]

\[\textbf{б)}\ 24\frac{17}{17} = 25\]

\[101\frac{10}{10} = 102\]

\[189\frac{3}{3} = 190\]

\[\boxed{\mathbf{7.}}\]

\[\textbf{а)}\ 1\frac{1}{8} - \frac{6}{8} = \frac{9}{8} - \frac{6}{8} = \frac{3}{8}\]

\[5\frac{2}{5} - \frac{3}{5} = 4\frac{7}{5} - \frac{3}{5} = 4\frac{4}{5}\]

\[4\frac{4}{9} - \frac{5}{6} = 4\frac{8}{18} - \frac{15}{18} =\]

\[= 3\frac{26}{18} - \frac{15}{18} = 3\frac{11}{18}\]

\[\textbf{б)}\ 3\frac{7}{16} - 1\frac{5}{8} = 3\frac{7}{16} - 1\frac{10}{16} =\]

\[= 1\frac{13}{16}\]

\[6\frac{2}{15} - 3\frac{2}{3} = 6\frac{2}{15} - 3\frac{10}{15} = 2\frac{7}{15}\]

\[12\frac{5}{8} - 5\frac{11}{12} = 12\frac{15}{24} - 5\frac{22}{24} =\]

\[= 6\frac{17}{24}\]