Решебник по математике 6 класс Виленкин Часть 1, 2 Часть 2. Задачи на повторение 18

\[\boxed{\mathbf{П.\ 18}}\]

\[\textbf{а)}\ 0,51 = \frac{51}{100} = \frac{357}{700};\ \ \ \]

\[\frac{17}{35} = \frac{340}{700}\]

\[0,51 > \frac{17}{35}\]

\[\textbf{б)}\ 0,56 = \frac{56}{100} = \frac{14}{25} = \frac{294}{525};\ \ \]

\[\frac{11}{21} = \frac{275}{525}\]

\[\frac{11}{21} < 0,56\]

\[\textbf{в)}\ \frac{13}{16} = \frac{169}{208};\ \ \ \frac{11}{13} = \frac{176}{208}\]

\[\frac{13}{16} < \frac{11}{13}\]

\[\textbf{г)}\ \frac{13}{15} = \frac{247}{285};\ \ \frac{15}{19} = \frac{225}{285}\]

\[\frac{13}{15} > \frac{15}{19}\]