Решебник по математике 6 класс Виленкин Часть 1, 2 Часть 2. Параграф 5. Решение уравнений Задание 16

\[\boxed{\text{5.\ 16}}\]

\[\textbf{а)}\ \frac{2}{3} \cdot ( - 1) = - \frac{2}{3}\]

\[\frac{2}{3} \cdot \frac{1}{3} = \frac{2}{9}\]

\[\frac{2}{3} \cdot \left( - 1\frac{1}{2} \right) = \frac{2}{3} \cdot \left( - \frac{3}{2} \right) = - 1\]

\[\frac{2}{3} \cdot ( - 3) = - 2\]

\[\frac{2}{3} \cdot \left( - \frac{1}{2} \right) = - \frac{1}{3}\]

\[1 \cdot ( - 1) = - 1\]

\[1 \cdot \frac{1}{3} = \frac{1}{3}\]

\[1 \cdot \left( - 1\frac{1}{2} \right) = - 1\frac{1}{2}\]

\[1 \cdot ( - 3) = - 3\]

\[1 \cdot \left( - \frac{1}{2} \right) = - \frac{1}{2}\]

\[- \frac{1}{2} \cdot ( - 1) = \frac{1}{2}\]

\[- \frac{1}{2} \cdot \frac{1}{3} = - \frac{1}{6}\]

\[- \frac{1}{2} \cdot \left( - 1\frac{1}{2} \right) = \frac{1}{2} \cdot \frac{3}{2} = \frac{3}{4}\]

\[- \frac{1}{2} \cdot ( - 3) = \frac{3}{2} = 1,5\]

\[- \frac{1}{2} \cdot \left( - \frac{1}{2} \right) = \frac{1}{4}\]

\[0 \cdot ( - 1) = 0\]

\[0 \cdot \frac{1}{3} = 0\]

\[0 \cdot \left( - 1\frac{1}{2} \right) = 0\]

\[0 \cdot ( - 3) = 0\]

\[0 \cdot \left( - \frac{1}{2} \right) = 0\]

\[- 2 \cdot ( - 1) = 2\]

\[- 2 \cdot \frac{1}{3} = - \frac{2}{3}\]

\[- 2 \cdot \left( - 1\frac{1}{2} \right) = 2 \cdot \frac{3}{2} = 3\]

\[- 2 \cdot ( - 3) = 6\]

\[- 2 \cdot \left( - \frac{1}{2} \right) = 1\]

\[\textbf{б)}\ \frac{1}{2}\ :2 = \frac{1}{2} \cdot \frac{1}{2} = \frac{1}{4}\]

\[\frac{1}{2}\ :\left( - \frac{1}{2} \right) = \frac{1}{2} \cdot ( - 2) = - 1\]

\[\frac{1}{2}\ :( - 6) = - \frac{1}{2} \cdot \frac{1}{6} = - \frac{1}{12}\]

\[\frac{1}{2}\ :\frac{1}{6} = \frac{1}{2} \cdot 6 = 3\]

\[\frac{1}{2}\ :\frac{1}{3} = \frac{1}{2} \cdot 3 = \frac{3}{2} = 1,5\]

\[- 3\ :2 = - \frac{3}{2} = - 1,5\]

\[- 3\ :\left( - \frac{1}{2} \right) = 3 \cdot 2 = 6\]

\[- 3\ :( - 6) = \frac{3}{6} = \frac{1}{2}\]

\[- 3\ :\frac{1}{6} = - 3 \cdot 6 = - 18\]

\[- 3\ :\frac{1}{3} = - 3 \cdot 3 = - 9\]

\[0\ :2 = 0\]

\[0\ :\left( - \frac{1}{2} \right) = 0\]

\[0\ :( - 6) = 0\]

\[0\ :\frac{1}{6} = 0\]

\[0\ :\frac{1}{3} = 0\]

\[- \frac{2}{3}\ :2 = - \frac{2}{3} \cdot \frac{1}{2} = - \frac{1}{3}\]

\[- \frac{2}{3}\ :\left( - \frac{1}{2} \right) = \frac{2}{3} \cdot 2 = \frac{4}{3} = 1\frac{1}{3}\]

\[- \frac{2}{3}\ :( - 6) = \frac{2}{3} \cdot \frac{1}{6} = \frac{1}{9}\]

\[- \frac{2}{3}\ :\frac{1}{6} = - \frac{2}{3} \cdot 6 = - 4\]

\[- \frac{2}{3}\ :\frac{1}{3} = - \frac{2}{3} \cdot 3 = - 2\]

\[- 1\ :2 = - \frac{1}{2}\]

\[- 1\ :\left( - \frac{1}{2} \right) = 2\]

\[- 1\ :( - 6) = \frac{1}{6}\]

\[- 1\ :\frac{1}{6} = - 6\]

\[- 1\ :\frac{1}{3} = - 3\]