Решебник по математике 6 класс Виленкин Часть 1, 2 Часть 2. Параграф 4. Действия с рациональными числами Задание 380

\[\boxed{\text{4.\ 380}}\]

\[\textbf{а)} - 1 \cdot \frac{1}{3} = - \frac{1}{3}\]

\[\frac{6}{11} \cdot \frac{1}{3} = \frac{2}{11}\]

\[- \frac{3}{7} \cdot \frac{1}{3} = - \frac{1}{7}\]

\[- 9 \cdot \frac{1}{3} = - 3\]

\[2\frac{2}{5} \cdot \frac{1}{3} = \frac{12}{5} \cdot \frac{1}{3} = \frac{4}{5} = 0,8\]

\[- 3 \cdot \frac{1}{3} = - 1\]

\[0,6 \cdot \frac{1}{3} = 0,2\]

\[- \frac{2}{5} \cdot \frac{1}{3} = - \frac{2}{15}\]

\[\textbf{б)}\ 6\ :\frac{3}{5} =\]

\[- 1\frac{1}{5}\ :\frac{3}{5} = - \frac{6}{5} \cdot \frac{5}{3} = - 2\]

\[- 3\ :\frac{3}{5} = - 3 \cdot \frac{5}{3} = - 5\]

\[- \frac{1}{2}\ :\frac{3}{5} = - \frac{1}{2} \cdot \frac{5}{3} = - \frac{5}{6}\]

\[\frac{9}{11}\ :\frac{3}{5} = \frac{9}{11} \cdot \frac{5}{3} = \frac{15}{11} = 1\frac{4}{11}\]

\[- 1\ :\frac{3}{5} = - 1 \cdot \frac{5}{3} = - \frac{5}{3} = - 1\frac{2}{3}\]

\[\frac{2}{3}\ :\frac{3}{5} = \frac{2}{3} \cdot \frac{5}{3} = \frac{10}{6} = 1\frac{4}{6} = 1\frac{2}{3}\]

\[- 1\frac{2}{3}\ :\frac{3}{5} = - \frac{5}{3} \cdot \frac{5}{3} = - \frac{25}{9} =\]

\[= - 2\frac{7}{9}\]