Решебник по математике 6 класс Виленкин Часть 1, 2 Часть 2. Параграф 4. Действия с рациональными числами Задание 349

\[\boxed{\text{4.\ 349}}\]

\[\textbf{а)} - 2\ :6 = - \frac{2}{6} = - \frac{1}{3}\]

\[- 2 - 11 = - 13\]

\[- 2 \cdot \frac{3}{4} = - \frac{3}{2} = - 1,5\]

\[- 2 + \frac{2}{3} = - 1\frac{1}{3}\]

\[- 2 + 2,5 = 0,5\]

\[- 2\ :\frac{2}{7} = - 2 \cdot \frac{7}{2} = - 7\]

\[- 2 - \frac{5}{6} = - 2\frac{5}{6}\]

\[- 2 \cdot \frac{1}{2} = - 1\]

\[\textbf{б)}\ 6 - \frac{5}{6} = 5\frac{1}{6}\]

\[- \frac{5}{6} \cdot 0 = 0\]

\[- \frac{5}{6} + 3 = 2\frac{1}{6}\]

\[- \frac{5}{6} - \frac{1}{3} = - \frac{5}{6} - \frac{2}{6} = - \frac{7}{6} = - 1\frac{1}{6}\]

\[- \frac{5}{6} \cdot 1\frac{1}{5} = - \frac{5}{6} \cdot \frac{6}{5} = - 1\]

\[- \frac{5}{6} + \frac{2}{3} = - \frac{5}{6} + \frac{4}{6} = - \frac{1}{6}\]

\[- \frac{5}{6} \cdot ( - 6) = 5\]