Решебник по математике 6 класс Виленкин Часть 1, 2 Часть 1. Параграф 3. Отношения и пропорции Задание 26

\[\boxed{\mathbf{3.26}}\]

\[\textbf{а)}\ 0,3 \cdot \frac{5}{6} = \frac{5}{20} = \frac{25}{100} = 0,25\]

\[\textbf{б)}\ \frac{5}{6}\ :0,6 = \frac{5}{6}\ :\frac{3}{5} = \frac{5}{6} \cdot \frac{5}{3} = \frac{25}{18} =\]

\[= 1\frac{7}{18}\]

\[\textbf{в)}\ \frac{2\frac{2}{7} + 1\frac{3}{14}}{3,5} = \frac{2\frac{4}{14} + 1\frac{3}{14}}{3,5} =\]

\[= \frac{3\frac{7}{14}}{3,5} = \frac{3,5}{3,5} = 1\]

\[\textbf{г)}\ \frac{6,3}{2\frac{1}{3} - 1\frac{1}{6}} = \frac{6,3}{2\frac{2}{6} - 1\frac{1}{6}} = \frac{6,3}{1\frac{1}{6}} =\]

\[= \frac{63}{10}\ :\frac{7}{6} = \frac{63}{10} \cdot \frac{6}{7} = \frac{54}{10} = 5,4\]

\[\textbf{д)}\ \frac{7,2 \cdot 1,6}{0,4 \cdot 0,8} = \frac{72 \cdot 16}{4 \cdot 8} = 9 \cdot 4 =\]

\[= 36\]

\[\textbf{е)}\ \frac{2,7}{0,09} = \frac{270}{9} = 30\]