Решебник по математике 6 класс Виленкин Часть 1, 2 Часть 1. Параграф 2. Действия со смешанными числами Задание 534

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\[\textbf{а)}\ \frac{7}{9}\ :\frac{7}{18} = \frac{7}{9} \cdot \frac{18}{7} = 2\]

\[\textbf{б)}\ \frac{1}{4}\ :\frac{1}{3} = \frac{1}{4} \cdot 3 = \frac{3}{4}\]

\[\textbf{в)}\ \frac{3}{4}\ :\frac{7}{9} = \frac{3}{4} \cdot \frac{9}{7} = \frac{27}{28}\]

\[\textbf{г)}\ \frac{3}{7}\ :\frac{1}{14} = \frac{3}{7} \cdot 14 = 3 \cdot 2 = 6\]

\[\textbf{д)}\ \frac{6}{11}\ :6 = \frac{6}{11} \cdot \frac{1}{6} = \frac{1}{11}\]

\[\textbf{е)}\ \frac{9}{13}\ :3 = \frac{9}{13} \cdot \frac{1}{3} = \frac{3}{13}\]

\[\textbf{ж)}\ \frac{5}{7}\ :\frac{1}{7} = \frac{5}{7} \cdot 7 = 5\]

\[\textbf{з)}\ 1\frac{1}{5}\ :3 = \frac{6}{5} \cdot \frac{1}{3} = \frac{2}{5} = 0,4\]

\[\textbf{и)}\ 12\ :\frac{4}{9} = 12 \cdot \frac{9}{4} = 3 \cdot 9 = 27\]

\[к)\ 1\frac{9}{14}\ :\frac{1}{7} = \frac{23}{14} \cdot 7 = \frac{23}{2} = 11\frac{1}{2}\]

\[л)\ 2\frac{4}{7}\ :1\frac{2}{7} = \frac{18}{7}\ :\frac{9}{7} = \frac{18}{7} \cdot \frac{7}{9} = 2\]

\[м)\ 4\frac{1}{36}\ :4\frac{5}{6} = \frac{145}{36}\ :\frac{29}{6} =\]

\[= \frac{145}{36} \cdot \frac{6}{29} = \frac{5}{6}\]