Решебник по математике 6 класс Виленкин Часть 1, 2 Часть 1. Параграф 2. Действия со смешанными числами Задание 528

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\[1)\ \frac{5}{9}\ :\frac{1}{5} = \frac{5}{9} \cdot 5 = \frac{25}{9}\]

\[\frac{5}{9}\ :1 = \frac{5}{9}\]

\[\frac{5}{9}\ :9 = \frac{5}{9} \cdot \frac{1}{9} = \frac{5}{81}\]

\[\frac{5}{9}\ :\frac{7}{5} = \frac{5}{9} \cdot \frac{5}{7} = \frac{25}{63}\]

\[\frac{5}{9}\ :\frac{1}{2} = \frac{5}{9} \cdot 2 = \frac{10}{9} = 1\frac{1}{9}\]

\[\frac{5}{9}\ :5 = \frac{5}{9} \cdot \frac{1}{5} = \frac{1}{9}\]

\[\frac{5}{9}\ :0,5 = \frac{5}{9}\ :\frac{1}{2} = \frac{5}{9} \cdot 2 = \frac{10}{9} =\]

\[= 1\frac{1}{9}\]

\[\frac{5}{9}\ :\frac{5}{7} = \frac{5}{9} \cdot \frac{7}{5} = \frac{7}{9}\]

\[2)\ 4\ :12 = \frac{4}{12} = \frac{1}{3}\]

\[4\ :1 = 4\]

\[4\ :0,4 = 40\ :4 = 10\]

\[4\ :\frac{8}{13} = 4 \cdot \frac{13}{8} = \frac{13}{2} = 6\frac{1}{2}\]

\[4\ :9 = \frac{4}{9}\]

\[4\ :\frac{1}{4} = 4 \cdot 4 = 16\]

\[4\ :\frac{1}{3} = 4 \cdot 3 = 12\]

\[4\ :\frac{4}{9} = 4 \cdot \frac{9}{4} = 9\]