\[\boxed{\mathbf{2.484}}\]
\[\textbf{а)}\ 4 > 4 \cdot \frac{1}{4}\]
\[\textbf{б)}\ 1\frac{4}{11} \cdot \frac{4}{9} > \frac{4}{9}\]
\[\textbf{в)}\ \frac{4}{7} < \frac{4}{7} \cdot \frac{8}{7}\]
\[\textbf{г)}\ \frac{14}{15} \cdot 1\frac{1}{14} = \frac{14}{15} \cdot \frac{15}{14} = 1\]