Решебник по математике 6 класс Виленкин Часть 1, 2 Часть 1. Параграф 2. Действия со смешанными числами Задание 404

\[\boxed{\mathbf{2.}\mathbf{404}}\]

\[\textbf{а)}\ \frac{2}{5} \cdot \frac{2}{5} = \frac{4}{25}\]

\[\frac{2}{5} \cdot 0 = 0\]

\[\frac{2}{5} + \frac{3}{5} = \frac{5}{5} = 1\]

\[\frac{2}{5} + 1 = \frac{2}{5} + \frac{5}{5} = \frac{7}{5}\]

\[\frac{2}{5} \cdot \frac{4}{5} = \frac{8}{25}\]

\[2\frac{1}{10} + \frac{2^{\backslash 2}}{5} = 2\frac{1}{10} + \frac{4}{10} =\]

\[= 2\frac{5}{10} = 2\frac{1}{2}\]

\[\frac{2^{\backslash 3}}{5} - \frac{1}{15} = \frac{6}{15} - \frac{1}{15} = \frac{5}{15} = \frac{1}{3}\]

\[\frac{2^{\backslash 4}}{5} - \frac{3}{20} = \frac{8}{20} - \frac{3}{20} = \frac{5}{20} = \frac{1}{4}\]

\[\textbf{б)}\ \frac{2}{5} \cdot 0 = 0\]

\[\frac{2}{5} \cdot \frac{5}{2} = \frac{10}{10} = 1\]

\[\frac{2}{5} + 2\frac{3}{5} = 2\frac{5}{5} = 3\]

\[\frac{2}{5} \cdot \frac{25}{32} = \frac{2 \cdot 25}{5 \cdot 32} = \frac{5}{16}\]

\[2\frac{4}{15} + \frac{2^{\backslash 3}}{5} = 2\frac{4}{15} + \frac{6}{15} = 2\frac{10}{15} =\]

\[= 2\frac{2}{3}\]

\[\frac{3}{16} \cdot \frac{2}{5} = \frac{3}{40}\]

\[\frac{2^{\backslash 13}}{5} - \frac{11}{65} = \frac{26}{65} - \frac{11}{65} = \frac{15}{65} = \frac{3}{13}\]

\[1\frac{14}{15} + \frac{2^{\backslash 3}}{5} = 1\frac{14}{15} + \frac{6}{15} = 1\frac{20}{15} =\]

\[= 2\frac{5}{15} = 2\frac{1}{3}\]