Решебник по математике 6 класс Виленкин Часть 1, 2 Часть 1. Параграф 2. Действия со смешанными числами Задание 316

\[\boxed{\mathbf{2.}\mathbf{316}}\]

\[a = \frac{3}{7}:\]

\[\frac{3}{7} \cdot \frac{3}{7} = \frac{9}{49}.\]

\[a = \frac{1}{2}:\]

\[\frac{3}{7} \cdot \frac{1}{2} = \frac{3}{14}.\]

\[a = 2\frac{1}{7} = \frac{15}{7}:\]

\[\frac{3}{7} \cdot \frac{15}{7} = \frac{45}{49}.\]

\[a = 2\frac{1}{3} = \frac{7}{3}:\]

\[\frac{3}{7} \cdot \frac{7}{3} = 1.\]

\[a = \frac{28}{33}:\]

\[\frac{3}{7} \cdot \frac{28}{33} = \frac{4}{11}.\]

\[b = \frac{1}{5}:\]

\[\frac{1}{5} \cdot \frac{5}{12} = \frac{1}{12}.\]

\[b = \frac{5}{12}:\]

\[\frac{5}{12} \cdot \frac{5}{12} = \frac{25}{144}.\]

\[b = 1\frac{1}{5} = \frac{6}{5}:\]

\[\frac{5}{12} \cdot \frac{6}{5} = \frac{1}{2}.\]

\[b = 2\frac{2}{5} = \frac{12}{5}:\]

\[\frac{5}{12} \cdot \frac{12}{5} = 1.\]