Решебник по математике 6 класс Виленкин Часть 1, 2 Часть 1. Параграф 2. Действия со смешанными числами Задание 251

\[\boxed{\mathbf{2.2}\mathbf{51}}\]

\[\textbf{а)}\ 1 - \frac{4}{17} = \frac{17}{17} - \frac{4}{17} = \frac{13}{17}\]

\[\textbf{б)}\ 5 - \frac{7}{13} = 4\frac{13}{13} - \frac{7}{13} = 4\frac{6}{13}\]

\[\textbf{в)}\ 6 - 5\frac{6}{11} = 5\frac{11}{11} - 5\frac{6}{11} = \frac{5}{11}\]

\[\textbf{г)}\ 4\frac{5}{9} - 3 = 1\frac{5}{9}\]

\[\textbf{д)}\ 4\frac{9^{\backslash 7}}{16} - 2\frac{3^{\backslash 8}}{14} =\]

\[= 4\frac{63}{112} - 2\frac{24}{112} = 2\frac{39}{112}\]

\[\textbf{е)}\ 11\frac{7^{\backslash 64}}{31} - 9\frac{11^{\backslash 31}}{64} =\]

\[= 11\frac{448}{1984} - 9\frac{341}{1984} = 2\frac{107}{1984}\]

\[\textbf{ж)}\ 17\frac{2^{\backslash 8}}{3} - 6\frac{7^{\backslash 3}}{8} =\]

\[= 17\frac{16}{24} - 6\frac{21}{24} =\]

\[= 16\frac{40}{24} - 6\frac{21}{24} = 10\frac{19}{24}\]

\[\textbf{з)}\ 24\frac{7^{\backslash 4}}{15} - 15\frac{5^{\backslash 5}}{12} =\]

\[= 24\frac{28}{60} - 15\frac{25}{60} = 9\frac{3}{60} = 9\frac{1}{20}\]