Решебник по математике 6 класс Мерзляк ФГОС Задание 992

\[\boxed{\mathbf{992\ (982).}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1) - 2,8 + x + 5,36 + ( - 7,2) +\]

\[+ y + ( - 7,36)\]

\[x = - 13;\ \ y = 54:\]

\[- 2,8 - 13 + 5,36 - 7,2 + 54 -\]

\[- 7,36 = - 10 + 41 - 2 = 29.\]

\[2)\ m + \left( - 2\frac{4}{9} \right) + 8\frac{13}{24} + n +\]

\[+ \left( - 3\frac{2}{9} \right) + \left( - 4\frac{5}{24} \right)\]

\[m = - 3\frac{5}{6};\ \ \ \ n = - 2\frac{11}{12}:\]

\[- 3\frac{5}{6} - 2\frac{4}{9} + 8\frac{13}{24} - 2\frac{11}{12} - 3\frac{2}{9} -\]

\[- 4\frac{5}{24} = - 3\frac{5}{6} - 5\frac{6}{9} + 4\frac{8}{24} -\]

\[- 2\frac{11}{12} =\]

\[= - 3\frac{5}{6} - 5\frac{2}{3} + 4\frac{1}{3} - 2\frac{11}{12} =\]

\[= - 3\frac{5}{6} - 1\frac{1}{3} - 2\frac{11}{12} =\]

\[= - 3\frac{10}{12} - 1\frac{4}{12} - 2\frac{11}{12} =\]

\[= - 6\frac{25}{12} = - 8\frac{1}{12}\]