Решебник по математике 6 класс Мерзляк ФГОС Задание 968

\[\boxed{\mathbf{968\ (}\mathbf{н}\mathbf{).}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \frac{2}{15} + \left( - \frac{3}{10} \right) = \frac{4}{30} - \frac{9}{30} =\]

\[= - \frac{5}{30} = - \frac{1}{6}\]

\[{2) - \frac{2}{3} + \frac{13}{15} = - \frac{10}{15} + \frac{13}{15} = }{= \frac{3}{15} = \frac{1}{5}}\]

\[3)\ - 4\frac{5}{9} + \left( - 7\frac{1}{6} \right) =\]

\[= - 4\frac{10}{18} - 7\frac{3}{18} = - 11\frac{13}{18}\]

\[4)\ - 5\frac{13}{18} + 12\frac{11}{12} =\]

\[= 12\frac{33}{36} - 5\frac{26}{36} = 7\frac{7}{36}\]

\[5)\ - 13 + 7\frac{3}{16} = - 12\frac{16}{16} +\]

\[+ 7\frac{3}{16} = - 5\frac{13}{16}\]

\[6)\ - 2\frac{3}{8} + \left( - 1\frac{5}{9} \right) = - 2\frac{27}{72} -\]

\[- 1\frac{40}{72} = - 3\frac{67}{72}\]

\[7)\ - 2\frac{9}{20} + 5\frac{7}{30} = - 2\frac{27}{60} +\]

\[+ 5\frac{14}{60} = 2\frac{47}{60}\]

\[8) - 5\frac{1}{4} + 1\frac{3}{8} = - 5\frac{2}{8} + 1\frac{3}{8} =\]

\[= - 3\frac{7}{8}\]

\[9)\ 4\frac{3}{7} + \left( - 8\frac{9}{14} \right) = 4\frac{6}{14} -\]

\[- 8\frac{9}{14} = - 4\frac{3}{14}\]