Решебник по математике 6 класс Мерзляк ФГОС Задание 958

\[\boxed{\mathbf{958\ (}\mathbf{с}\mathbf{).}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \frac{2}{15} + \left( - \frac{3}{10} \right) = \frac{4}{30} - \frac{9}{30} =\]

\[= - \frac{5}{30} = - \frac{1}{6}\]

\[2) - \frac{2}{3} + \frac{13}{15} = - \frac{10}{15} + \frac{13}{15} =\]

\[= \frac{3}{15} = \frac{1}{5}\]

\[3)\frac{13}{16} + \left( - \frac{9}{32} \right) = \frac{26}{32} - \frac{9}{32} = \frac{17}{32}\]

\[4) - 4\frac{5}{9} + \left( - 7\frac{1}{6} \right) = - 4\frac{10}{18} -\]

\[- 7\frac{3}{18} = - 11\frac{13}{18}\]

\[5) - 5\frac{7}{8} + \left( - 6\frac{3}{10} \right) = - 5\frac{35}{40} -\]

\[- 6\frac{12}{40} = - 11\frac{47}{40} = - 12\frac{7}{40}\]

\[6) - 5\frac{13}{18} + 12\frac{11}{12} = - 5\frac{26}{36} +\]

\[+ 12\frac{33}{36} = 7\frac{7}{36}\]

\[7) - 13 + 7\frac{3}{16} = - 5\frac{13}{16}\]

\[8) - 2\frac{3}{8} + \left( - 1\frac{5}{9} \right) = - 2\frac{27}{72} -\]

\[- 1\frac{40}{72} = - 3\frac{67}{72}\]

\[9) - 8 + 4\frac{5}{22} = - 3\frac{17}{22}\]

\[10) - 2\frac{9}{20} + 5\frac{7}{30} = - 2\frac{27}{60} +\]

\[+ 5\frac{14}{60} = 2\frac{47}{60}\]

\[11) - 5\frac{1}{4} + 1\frac{3}{8} = - 5\frac{2}{8} + 1\frac{3}{8} =\]

\[= - 3\frac{7}{8}\]

\[12)\ 4\frac{3}{7} + \left( - 8\frac{9}{14} \right) = 4\frac{6}{14} -\]

\[- 8\frac{9}{14} = - 4\frac{3}{14}\]