Решебник по математике 6 класс Мерзляк ФГОС Задание 93

 

\[\boxed{\mathbf{93\ (93)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[Нет,\ стоимость\ покупки\ \]

\[должна\ быть\ кратна\ трем.\]

\[\ 3x + 45 + 24y + 6z =\]

\[= 3 \cdot (x + 15 + 8y + 2z) \Longrightarrow то\ \]

\[есть,\ стоимость\ покупки\ \]

\[кратна\ 3,\ а\ 260\ рублей\ не\ \]

\[кратно\ 3.\]

\[Ответ:не\ может.\]

\[\boxed{\mathbf{93}.}\]

\[1)\ (208 + x) - 416 = 137\]

\[208 + x = 137 + 416\]

\[208 + x = 553\]

\[x = 553 - 208\]

\[x = 345.\]

\[2)\ (801 - b) - 224 = 368\]

\[801 - b = 368 + 224\]

\[801 - b = 592\]

\[b = 801 - 592\]

\[b = 209.\]

\[3)\ 972 - (y - 504) = 284\]

\[y - 504 = 972 - 284\]

\[y - 504 = 688\]

\[y = 688 + 504\]

\[y = 1192.\]

\[4)\ 643 - (581 - b) = 243\]

\[581 - b = 643 - 243\]

\[581 - b = 400\]

\[b = 581 - 400\]

\[b = 181.\]

\[5)\ (38 + x) \cdot 13 = 650\]

\[38 + x = 650\ :13\]

\[38 + x = 50\]

\[x = 50 - 38\]

\[x = 12.\]

\[6)\ 18 \cdot (47 - m) = 324\]

\[47 - m = 324\ :18\]

\[47 - m = 18\]

\[m = 47 - 18\]

\[m = 29.\]

\[7)\ (y + 100)\ :17 = 9\]

\[y + 100 = 9 \cdot 17\]

\[y + 100 = 153\]

\[y = 153 - 100\]

\[y = 53.\]

\[8)\ 240\ :(c - 15) = 60\]

\[c - 15 = 240\ :60\]

\[c - 15 = 40\]

\[c = 40 + 15\]

\[c = 55.\]