Решебник по математике 6 класс Мерзляк ФГОС Задание 543

 

\[\boxed{\mathbf{543\ (543).}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

Пояснение.

Решение.

\[1)\ \frac{3}{8} = \frac{3 \cdot 125}{8 \cdot 125} = \frac{375}{1000} = 0,375\]

\[2)\ \frac{32}{125} = \frac{32 \cdot 8}{125 \cdot 8} = \frac{256}{1000} =\]

\[= 0,256\]

\[3)\ \frac{159}{200} = \frac{159 \cdot 5}{200 \cdot 5} = \frac{795}{1000} =\]

\[= 0,795\]

\[4)\ \frac{1}{25} = \frac{1 \cdot 4}{25 \cdot 4} = \frac{4}{100} = 0,04\]

\[5)\ \frac{53}{50} = \frac{53 \cdot 2}{50 \cdot 2} = \frac{106}{100} = 1,06\]

\[6)\ \frac{56}{175} = \frac{8}{25} = \frac{8 \cdot 4}{25 \cdot 4} = \frac{32}{100} =\]

\[= 0,32\]

\[\boxed{\mathbf{5}\mathbf{43}}\]

\[1)\ 9x = 5\]

\[x = 5\ :9\]

\[x = 0,(5)\]

\[x \approx 0,56.\]

\[2)\ 8\ :x = 125\]

\[x = 8\ :125\]

\[x = 0,064\]

\[x \approx 0,06.\]

\[3)\ 3x = 4\]

\[x = 4\ :3\]

\[x = 1,(3)\]

\[x \approx 1,33.\]

\[4)\ \frac{2}{7}x = 1\frac{1}{6}\]

\[x = \frac{7}{6}\ :\frac{2}{7}\]

\[x = \frac{7 \cdot 7}{6 \cdot 2}\]

\[x = \frac{49}{12}\]

\[x = 4,08(3)\]

\[x \approx 4,08.\]