Решебник по математике 6 класс Мерзляк ФГОС Задание 383

\[\boxed{\mathbf{383\ (383).}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \frac{14}{3} = 4\frac{2}{3} \Longrightarrow \frac{14}{3} > 4\]

\[2)\ \frac{12}{5} = 2\frac{2}{5} \Longrightarrow \frac{12}{5} < 3\]

\[3)\ \frac{35}{6} = 5\frac{5}{6} \Longrightarrow 6 > \frac{35}{6}\]

\[\boxed{\mathbf{383}\mathbf{.}}\]

\[1)\ 7\frac{7^{\backslash 4}}{9} - 4\frac{1^{\backslash 3}}{12} + 2\frac{3^{\backslash 9}}{4} =\]

\[= 5 + \frac{28 - 3 + 27}{36} = 5 + \frac{52}{36} =\]

\[= 2 + 1\frac{16}{36} = 2 + 1\frac{4}{9} = 3\frac{4}{9}\]

\[2)\ 10\frac{9}{16} - \left( 3\frac{11^{\backslash 3}}{12} + 4\frac{4^{\backslash 4}}{9} \right) =\]

\[= 10\frac{9}{16} - \left( 3\frac{33}{36} + 4\frac{16}{36} \right) =\]

\[= 10\frac{9}{16} - 7\frac{49}{36} =\]

\[= 10\frac{9^{\backslash 9}}{16} - 8\frac{13^{\backslash 4}}{36} =\]

\[= 10\frac{81}{144} - 8\frac{52}{144} = 2\frac{29}{144}\]