Решебник по математике 6 класс Мерзляк ФГОС Задание 347

\[\boxed{\mathbf{347\ (347).}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

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\[1)\ \frac{5}{13} \cdot \frac{2}{3} = \frac{5 \cdot 2}{13 \cdot 3} = \frac{10}{39}\]

\[2)\ \frac{7}{12} \cdot \frac{3}{14} = \frac{7 \cdot 3}{12 \cdot 14} = \frac{1 \cdot 1}{4 \cdot 2} = \frac{1}{8}\]

\[3)\ 1\frac{1}{2} \cdot \frac{1}{6} = \frac{3}{2} \cdot \frac{1}{6} = \frac{3}{2 \cdot 6} = \frac{1}{4}\]

\[4)\ 3\frac{5}{9} \cdot 5\frac{1}{4} = \frac{32}{9} \cdot \frac{21}{4} = \frac{32 \cdot 21}{9 \cdot 4} =\]

\[= \frac{8 \cdot 7}{3 \cdot 1} = \frac{56}{3} = 18\frac{2}{3}\]

\[5)\ 2\frac{1}{7} \cdot 2\frac{4}{5} = \frac{15}{7} \cdot \frac{14}{5} = \frac{15 \cdot 14}{7 \cdot 5} =\]

\[= 3 \cdot 2 = 6\]

\[6)\ 1\frac{13}{15} \cdot \frac{5}{8} \cdot 2\frac{2}{7} = \frac{28}{15} \cdot \frac{5}{8} \cdot \frac{16}{7} =\]

\[= \frac{28 \cdot 5 \cdot 16}{15 \cdot 8 \cdot 7} = \frac{4 \cdot 1 \cdot 2}{3 \cdot 1 \cdot 1} = \frac{8}{3} =\]

\[= 2\frac{2}{3}\]