Решебник по математике 6 класс Мерзляк ФГОС Задание 330

\[\boxed{\mathbf{330\ (330).}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 2 \cdot (x + 7) = 2 \cdot x + 2 \cdot 7 =\]

\[= 2x + 14\]

\[2)\ 7 \cdot (5 - a) = 7 \cdot 5 - 7 \cdot a =\]

\[= 35 - 7a\]

\[3)\ (c - 0,4) \cdot 1,2 =\]

\[= c \cdot 1,2 - 0,4 \cdot 1,2 =\]

\[= 1,2c - 0,48\]

\[\boxed{\mathbf{330}\mathbf{\ (239)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \frac{1}{4}\ и\ \frac{1}{6} \Longrightarrow \frac{3}{12}\ и\ \frac{2}{12}\]

\[2)\ \frac{4}{9}\ и\ \frac{7}{12}\ \Longrightarrow \frac{16}{36}\ и\ \frac{21}{36}\]

\[3)\ \frac{5}{6}\ и\ \frac{7}{18} \Longrightarrow \frac{15}{18}\ и\frac{7}{18}\]

\[4)\ \frac{3}{8}\ и\ \frac{4}{15} \Longrightarrow \frac{45}{120}\ и\ \frac{32}{120}\]

\[5)\ \frac{2}{15}\ и\ \frac{11}{12} \Longrightarrow \frac{8}{60}\ и\ \frac{55}{60}\]

\[6)\ \frac{1}{12}\ и\ \frac{1}{18} \Longrightarrow \frac{3}{36}\ и\ \frac{2}{36}\]

\[7)\ \frac{1}{24}\ и\ \frac{1}{18} \Longrightarrow \frac{3}{72}\ и\ \frac{4}{72}\]

\[8)\ \frac{3}{10};\ \ \frac{3}{8}\ и\ \ \frac{3}{4} \Longrightarrow \frac{12}{40};\ \ \frac{15}{40}\ и\ \frac{30}{40}\]