Решебник по математике 6 класс Мерзляк ФГОС Задание 283

 

\[\boxed{\mathbf{283\ (284)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 0,8 - \frac{5}{7} = \frac{8}{10} - \frac{5}{7} =\]

\[= \frac{4^{\backslash 7}}{5} - \frac{5^{\backslash 5}}{7} = \frac{28 - 25}{35} = \frac{3}{35}\]

\[2)\ 0,\ 36 + \frac{8}{15} = \frac{36}{100} + \frac{8}{15} =\]

\[= \frac{9^{\backslash 3}}{25} + \frac{8^{\backslash 5}}{15} = \frac{27 + 40}{75} = \frac{67}{75}\]

\[3)\ 7\frac{7}{8} - 3,18 = 7\frac{7}{8} - 3\frac{18}{100} =\]

\[= 7\frac{7^{\backslash 25}}{8} - 3\frac{9^{\backslash 4}}{50} =\]

\[= 7\frac{175}{200} - 3\frac{36}{200} = 4\frac{139}{200}\]

\[4)\ 4,75 - 2\frac{3}{16} = 4\frac{75}{100} - 2\frac{3}{16} =\]

\[= 4\frac{3^{\backslash 4}}{4} - 2\frac{3}{16} = 4\frac{12}{16} - 2\frac{3}{16} =\]

\[= 2\frac{9}{16}\]

\[\boxed{\mathbf{283\ (}\mathbf{с}\mathbf{)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 6\frac{3}{11} + x = 10\frac{6}{7}\text{\ \ }\]

\[x = 10\frac{6^{\backslash 11}}{7} - 6\frac{3^{\backslash 7}}{11}\]

\[x = 10\frac{66}{77} - 6\frac{21}{77}\]

\[x = 4\frac{45}{77}\]

\[Ответ:4\frac{45}{77}.\]

\[2)\ 9\frac{5}{36} - x = 2\frac{4}{9}\text{\ \ \ \ \ }\]

\[x = 9\frac{5}{36} - 2\frac{4^{\backslash 4}}{9}\]

\[x = 8\frac{41}{36} - 2\frac{16}{36}\]

\[x = 6\frac{25}{36}\]

\[Ответ:6\frac{25}{36}.\]

\[3)\ x - 5\frac{17}{60} = 7\frac{9}{20}\text{\ \ \ }\]

\[x = 7\frac{9^{\backslash 3}}{20} + 5\frac{17}{60}\]

\[x = 7\frac{27}{60} + 5\frac{17}{60}\]

\[x = 12\frac{44}{60} = 12\frac{11}{15}\]

\[Ответ:12\frac{11}{15}.\]

\[\boxed{\mathbf{283}\mathbf{.}}\]

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