Решебник по математике 6 класс Мерзляк ФГОС Задание 277

\[\boxed{\mathbf{277\ (276)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 5\frac{7^{\backslash 5}}{8} + 6\frac{3^{\backslash 4}}{10} = 5\frac{35}{40} + 6\frac{12}{40} =\]

\[= 11\frac{47}{40} = 12\frac{7}{40}\]

\[2)\ 6\frac{3^{\backslash 9}}{8} + 2\frac{5^{\backslash 8}}{9} = 6\frac{27}{72} + 2\frac{40}{72} =\]

\[= 8\frac{67}{72}\]

\[3)\ 1\frac{8^{\backslash 2}}{21} + 4\frac{3^{\backslash 3}}{14} + 2\frac{2^{\backslash 6}}{7} =\]

\[= 1\frac{16}{42} + 4\frac{9}{42} + 2\frac{12}{42} = 7\frac{37}{42}\]

\[\boxed{\mathbf{277\ (}\mathbf{с}\mathbf{)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 8\frac{9}{14} - 3\frac{3^{\backslash 2}}{7} = 8\frac{9}{14} - 3\frac{6}{14} =\]

\[= 5\frac{3}{14}\]

\[2)\ 7\frac{5^{\backslash 2}}{12} - 3\frac{7}{24} = 7\frac{10}{24} - 3\frac{7}{24} =\]

\[= 4\frac{3}{24} = 4\frac{1}{8}\]

\[3)\ 12\frac{11^{\backslash 3}}{12} - 5\frac{13^{\backslash 2}}{18} =\]

\[= 12\frac{33}{36} - 5\frac{26}{36} = 7\frac{7}{36}\]

\[\boxed{\mathbf{277}\mathbf{.}}\]