Решебник по математике 6 класс Мерзляк ФГОС Задание 266

 

\[\boxed{\mathbf{266\ (265)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \frac{5}{11} + \frac{3}{11} = \frac{8}{11}\]

\[2)\ \frac{7}{15} - \frac{4}{15} = \frac{3}{15} = \frac{1}{5}\]

\[3)\ 6 + \frac{5}{13} = 6\frac{5}{13}\]

\[4)\ 2\frac{4}{13} + 5\frac{2}{13} = 7\frac{6}{13}\]

\[5)\ 4\frac{11}{18} - 1\frac{5}{18} = 3\frac{6}{18} = 3\frac{1}{3}\ \]

\[6)\ 1 - \frac{9}{16} = \frac{16}{16} - \frac{9}{16} = \frac{7}{16}\]

\[7)\ 6 - 3\frac{7}{11} = 5\frac{11}{11} - 3\frac{7}{11} = 2\frac{4}{11}\]

\[8)\ 7\frac{2}{9} - 2\frac{5}{9} = 6\frac{11}{9} - 2\frac{5}{9} =\]

\[= 4\frac{6}{9} = 4\frac{2}{3}\]

\[\boxed{\mathbf{266\ (}\mathbf{с}\mathbf{)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \frac{5}{16} + x = \frac{11}{16}\text{\ \ \ \ \ \ }\]

\[x = \frac{11}{16} - \frac{5}{16}\]

\[x = \frac{6}{16} = \frac{3}{8}\]

\[Ответ:x = \frac{3}{8}.\]

\[2)\ \left( \frac{17}{28} - x \right) - \frac{11}{28} = \frac{3}{28}\text{\ \ \ \ }\]

\[\frac{17}{28} - x = \frac{3}{28} + \frac{11}{28}\text{\ \ \ \ \ }\]

\[\frac{17}{28} - x = \frac{14}{28}\]

\[x = \frac{17}{28} - \frac{14}{28}\]

\[x = \frac{3}{28}\]

\[Ответ:x = \frac{3}{28}.\]

\[\boxed{\mathbf{266}\mathbf{.}}\]

\[1)\ Принадлежат\ кругу:\]

\[K;N;O;P;S;T.\]

\[Не\ принадлежат\ кругу:\ \]

\[\text{M.}\]

\[2)\ Радиусы\ круга:\]

\[OK;ON;OS;OT.\]

\[3)\ OM > радиуса;\]

\[OP < радиуса.\]