Решебник по математике 6 класс Мерзляк ФГОС Задание 259

 

\[\boxed{\mathbf{259\ (}\mathbf{н}\mathbf{)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \frac{1}{6} < x < \frac{1}{2}\]

\[\frac{2}{12} < x < \frac{6}{12}\]

\[\frac{3}{12} = \frac{1}{4};\ \ \frac{4}{12} = \frac{1}{3};\ \ \frac{5}{12}.\]

\[Ответ:\ x = \frac{1}{4};\ \frac{1}{3};\ \frac{5}{12}.\]

\[2)\ \frac{3}{5} < x < \frac{4}{5}\]

\[\frac{15}{25} < x < \frac{20}{25}\]

\[\frac{16}{25};\ \ \frac{17}{25};\ \frac{18}{25}.\]

\[Ответ:\ \frac{16}{25};\ \frac{17}{25};\ \frac{19}{25}.\]

\[\boxed{\mathbf{259\ (}\mathbf{с}\mathbf{)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \frac{1}{3} < x < \frac{1}{2}\]

\[\frac{8}{24} < x < \frac{12}{24}\]

\[\frac{9}{24} = \frac{3}{8};\ \ \ \ \frac{10}{24} = \frac{5}{12};\ \ \ \ \frac{11}{24}\]

\[Ответ:\ x = \frac{3}{8};\ \ \frac{5}{12};\ \ \frac{11}{24}.\]

\[2)\ \frac{3}{5} < x < \frac{4}{5}\]

\[\frac{12}{20} < x < \frac{16}{20}\]

\[\frac{13}{20};\ \ \frac{14}{20} = \frac{7}{10};\ \ \frac{15}{20} = \frac{3}{4}\]

\[Ответ:\ x = \frac{13}{20};\ \frac{7}{10};\ \frac{3}{4}.\]

\[3)\ \ \frac{99^{\backslash 4}}{98} < x < 1\]

\[\frac{392}{396} < x < \frac{393}{396}\]

\[\frac{393}{396} = \frac{131}{132};\ \ \frac{394}{396}\ = \frac{197}{198};\ \ \ \frac{395}{396}\]

\[Ответ:\ x = \frac{131}{132};\ \frac{197}{198};\ \frac{395}{396}\text{.\ \ }\]

\[\boxed{\mathbf{259}\mathbf{.}}\]

\[P = 8 + 8 + 10 + 10 = 36\ см.\]

\[Ответ:36\ см.\]