Решебник по математике 6 класс Мерзляк ФГОС Задание 254

\[\boxed{\mathbf{254\ (254)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \frac{12}{23} < \frac{x}{23} < 1\ \ \]

\[x = 13,\ 14,\ 15,\ 16,\ 17,\ 18,\ 19,\ 20,\ \]

\[21,\ 22.\]

\[2)\ \frac{4}{9} < \frac{x}{36} < \frac{11}{12}\text{\ \ \ }\]

\[\frac{16}{36} < \frac{x}{36} < \frac{33}{36}\text{\ \ \ }\]

\[x = 17,\ 18,\ 19,\ 20,\ 21,\ 22,\ 23,\ 24,\ \]

\[25,\ 26,\ 27,\ 28,\ 29,\ 30,\ 31,\ 32.\]

\[\boxed{\mathbf{254}\mathbf{.}}\]

\[P_{\text{ABCD}} = 42\ см;\]

\[P_{\text{ABCDE}} = 64\ см;\]

\[AD = 14\ см;\]

\[P_{\text{AED}} - ?\]

\[P_{\text{ABCDE}} = P_{\text{ABCD}} + P_{\text{AED}} - 2AD\]

\[64 = 42 + P_{\text{AED}} - 2 \cdot 14\]

\[42 - 28 + P_{\text{AED}} = 64\]

\[14 + P_{\text{AED}} = 64\]

\[P_{\text{AED}} = 64 - 14 = 50\ (см).\]

\[Ответ:50\ см.\]