Решебник по математике 6 класс Мерзляк ФГОС Задание 242

\[\boxed{\mathbf{242\ (242)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

Пояснение.

Решение.

\[1)\ \frac{5}{6} = \frac{55}{66};\ \ \ \ \frac{7}{11} = \frac{42}{66} \Longrightarrow\]

\[\Longrightarrow \frac{5}{6} > \frac{7}{11}\]

\[2)\ \frac{7}{13} = \frac{112}{208};\ \ \ \ \frac{7}{16} = \frac{91}{208} \Longrightarrow\]

\[\Longrightarrow \frac{7}{13} > \frac{7}{16}\]

\[{3)\ \frac{3}{8} = \frac{9}{24};\ \ \ \frac{1}{6} = \frac{4}{24} \Longrightarrow }{\Longrightarrow \frac{3}{8} > \frac{1}{6}}\]

\[4)\ \frac{5}{8} = \frac{25}{40};\ \ \ \ \frac{7}{10} = \frac{28}{40} \Longrightarrow\]

\[\Longrightarrow \frac{5}{8} < \frac{7}{10}\]

\[5)\ \frac{3}{7} = \frac{9}{21};\ \ \ \ \frac{9}{21} \Longrightarrow \frac{3}{7} = \frac{9}{21}\]

\[6)\ \frac{3}{5} = \frac{24}{40};\ \ \ \ \frac{5}{8} = \frac{25}{40} \Longrightarrow \frac{3}{5} < \frac{5}{8}\]

\[7)\ \frac{7}{12} = \frac{21}{36};\ \ \ \ \ \frac{11}{18} = \frac{22}{36} \Longrightarrow\]

\[\Longrightarrow \frac{7}{12} < \frac{11}{18}\]

\[8)\ \frac{10}{21} = \frac{20}{42};\ \ \ \ \frac{9}{14} = \frac{27}{42} \Longrightarrow\]

\[\Longrightarrow \frac{10}{21} < \frac{9}{14}\]

\[\boxed{\mathbf{242}\mathbf{.}}\]

\[S_{\text{AMOK}} = 8\ см^{2}.\]

\[1)\ S_{\text{AMO}} = 8\ :2 = 4\ см^{2}.\]

\[2)\ S_{\text{AOB}} = 4 + 4 = 8\ см^{2}.\]

\[3)\ S_{\text{ABD}} = 8 + 4 \cdot 2 = 16\ см^{2}.\]

\[4)\ S_{\text{AOD}} = 4 + 4 = 8\ см^{2}.\]