Решебник по математике 6 класс Мерзляк ФГОС Задание 202

 

\[\boxed{\mathbf{202\ }\left( \mathbf{202} \right)\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

Пояснение.

Решение.

\[1)\ \frac{x - 2}{36} = \frac{5}{12}\text{\ \ \ }\]

\[\frac{x - 2}{36} = \frac{15}{36}\text{\ \ \ \ }\]

\[x - 2 = 15\ \ \]

\[x = 17\]

\[Ответ:17.\]

\[2)\ \frac{x - 5}{23} = \frac{36}{92}\text{\ \ }\]

\[\frac{x - 5}{23} = \frac{9}{23}\text{\ \ }\]

\[x - 5 = 9\ \ \ \]

\[x = 14\]

\[Ответ:14.\]

\[3)\ \frac{4}{3x - 11} = \frac{36}{63}\text{\ \ }\]

\[\frac{4}{3x - 11} = \frac{4}{7}\text{\ \ }\]

\[3x - 11 = 7\ \ \ \]

\[3x = 18\ \ \ \ \]

\[x = 6\]

\[Ответ:6.\]

\[\boxed{\mathbf{202}\mathbf{.}}\]

\[AM - \text{x\ }см;\]

\[BM - (x + 7)\ см;\]

\[AB = 29\ см.\]

\[x + x + 7 = 29\]

\[2x = 29 - 7\]

\[2x = 22\]

\[x = 11\ (см) - отрезок\ \text{AM.}\]

\[x + 7 = 11 + 7 = 18\ (см) -\]

\[отрезок\ \text{BM.}\]

\[Ответ:11\ см\ и\ 18\ см.\]