Решебник по математике 6 класс Мерзляк ФГОС Задание 1354

 

\[\boxed{\mathbf{1354}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ 0,3 \cdot (1,2x - 0,5y) -\]

\[- 1,5 \cdot (0,4x + y) = 0,36x -\]

\[- 0,15y - 0,6x - 1,5y =\]

\[= - 0,24x - 1,65y.\]

\[2) - 2,4 \cdot (2,5a - 1,5b) +\]

\[+ 0,5 \cdot (1,8b + 5,6a) = - 6a +\]

\[+ 3,6b + 0,9b + 2,8a =\]

\[= 4,5b - 3,2a.\]

\[3) - 1,8 \cdot (3,5m - 5) -\]

\[- 6,5 \cdot (0,8 - 0,4m) =\]

\[= - 6,3m + 9 - 5,2 + 2,6m =\]

\[= 3,8 - 3,7m.\ \]

\[4)\ \frac{4}{9} \cdot \left( 1\frac{1}{2}c - \frac{3}{8} \right) -\]

\[- \left( 1\frac{5}{6} - 1\frac{1}{3}c \right) = \frac{4}{9} \cdot \frac{3}{2}c -\]

\[- \frac{4}{9} \cdot \frac{3}{8} - 1\frac{5}{6} + 1\frac{1}{3}c =\]

\[= \frac{2}{3}c - \frac{1}{3 \cdot 2} - 1\frac{5}{6} + 1\frac{1}{3}c =\]

\[= 2\ c - \frac{1}{6} - 1\frac{5}{6} = 2c - 2.\ \]

\[5)\ 1,2 \cdot \left( \frac{5}{6}k + 0,4n \right) -\]

\[- 1,8 \cdot \left( \frac{5}{9}k - 0,3n \right) =\]

\[= 0,2 \cdot 5k + 0,48n - 0,2 \cdot 5k +\]

\[+ 0,54n = 1,02n\]

\[6)\ \left( \frac{1}{6}a + 6,5 \right) - \left( 2\frac{7}{9}a + 3\frac{1}{3} \right) =\]

\[= \frac{1}{6}a + 6,5 - 2\frac{7}{9}a - 3\frac{1}{3} =\]

\[= \frac{3}{18}a - 2\frac{14}{18}a + 6\frac{1}{2} - 3\frac{1}{3} =\]

\[= - 2\frac{11}{18}a + 6\frac{3}{6} - 3\frac{2}{6} =\]

\[= 3\frac{1}{6} - 2\frac{11}{18}\text{a.\ }\]

\[7)\ \frac{3}{7} \cdot (0,56x - 4,9y) -\]

\[- \frac{6}{13} \cdot (0,52x - 3,9y) =\]

\[= 3 \cdot 0,08x - 3 \cdot 0,7y -\]

\[- 6 \cdot 0,04x + 6 \cdot 0,3y =\]

\[= 0,24x - 0,24x - 2,1y +\]

\[+ 1,8y = - 0,3y.\ \]

\[8)\ 6 \cdot \left( \frac{1}{4}k - \frac{5}{6} \right) -\]

\[- 15 \cdot \left( 0,6 - 2\frac{1}{3}k \right) = \frac{3}{2}k -\]

\[- 5 - 9 + 15 \cdot \frac{7}{3}k =\]

\[= 1\frac{1}{2}k + 5 \cdot 7k - 14 = 1,5k +\]

\[+ 35k - 14 = 36,5k - 14.\ \ \ \]