Решебник по математике 6 класс Мерзляк ФГОС Задание 1134

 

\[\boxed{\mathbf{1134\ (1126)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1) - 3y - 9y + 5y = 2,1\]

\[- 7y = 2,1\]

\[y = 2,1\ :( - 7)\]

\[y = - 0,3\]

\[Ответ:\ - 0,3.\]

\[2) - 2,4m + 3,8m + 1,2m =\]

\[= - 0,052\]

\[2,6m = - 0,052\]

\[m = - 0,052\ :2,6\]

\[m = - 0,02\]

\[Ответ:\ - 0,02.\]

\[3) - \frac{3}{7}a + \frac{5}{6}a - \frac{8}{21}a = - \frac{1}{49}\]

\[\frac{- 18 + 35 - 16}{42}a = - \frac{1}{49}\]

\[\frac{1}{42}a = - \frac{1}{49}\]

\[a = - \frac{6}{7}\]

\[Ответ:\ - \frac{6}{7}.\]

\[4) - 8\frac{7}{16}c + 10\frac{19}{24}c -\]

\[- 3\frac{3}{8}c = - 3\frac{1}{16}c\]

\[\left( - 8\frac{21}{48} + 10\frac{38}{48} - 3\frac{18}{48} \right)c =\]

\[= - 3\frac{1}{16}\]

\[\left( 10\frac{38}{48} - 11\frac{39}{48} \right)c = - 3\frac{1}{16}\]

\[- 1\frac{1}{48}c = - 3\frac{1}{16}\]

\[c = - 3\frac{1}{16}\ :\left( - 1\frac{1}{48} \right)\]

\[Ответ:3.\]

\[5)\ 2,3x - ( - 7,2)x +\]

\[+ x( - 1,5) = - 2,4\]

\[(2,3 + 7,2 - 1,5)x = - 2,4\]

\[8x = - 2,4\]

\[x = - 2,4\ :8\]

\[x = - 0,3\]

\[Ответ:\ - 0,3.\]

\[6)\ 3,4y + y \cdot ( - 8,1) -\]

\[- ( - 2,2)y = - 10\]

\[(3,4 - 8,1 + 2,2)y = - 10\]

\[- 2,5y = - 10\]

\[y = - 10\ :( - 2,5)\]

\[y = 4\]

\[Ответ:4.\]